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14x^2-63x-70=0
a = 14; b = -63; c = -70;
Δ = b2-4ac
Δ = -632-4·14·(-70)
Δ = 7889
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7889}=\sqrt{49*161}=\sqrt{49}*\sqrt{161}=7\sqrt{161}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-63)-7\sqrt{161}}{2*14}=\frac{63-7\sqrt{161}}{28} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-63)+7\sqrt{161}}{2*14}=\frac{63+7\sqrt{161}}{28} $
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